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JAVA

User Thrown Exception

import java.util.*;
public class UserExceptionThrow 
{
int n; 
UserExceptionThrow(int n)
{
this.n = n;
}

int calculate() throws NumberFormatException
{
Random r;
r = new Random(); 
int x = r.nextInt(); 
int y = r.nextInt();
if (x > 100000)
throw new NumberFormatException("X Leads to be Greater than One Lakh");

try
{
n *= x / y;
}
catch(ArithmeticException e)
{
System.out.println("Division by Zero");
}
catch(NumberFormatException e)
{
System.out.println("X Leads to be Greater than One Lakh");
}
return n;
}
public static void main(String arg[])
{
UserExceptionThrow u;
u = new UserExceptionThrow(1000);
while (u.n < 10000)
{
u.n =u.calculate();
}
}
}

Output : X Leads to be Greater than One Lakh

 


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